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A. \[5.72c{{m}^{2}}\]

B. \[8.01c{{m}^{2}}\]

C.\[10.26c{{m}^{2}}\]

D. \[13.13c{{m}^{2}}\]

Answer

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Hint:- Find the degree of the clock for 1 hour. Then find the degree of the clock for 1 minute. Use area of sector to find the area swept by a minute hand in 1 minute.

__Complete step-by-step solution -__

The minute hand of a clock completes a full circle degree in 1 hour. Consider the clock given below. The degree swept by the minute hand in 1 hour is \[{{360}^{\circ }}\] , i.e. the clock resembles circle and the degree of a circle is \[{{360}^{\circ }}\] . Thus it will be easier to remember that the degree swept by minute hand in 1 hour is \[{{360}^{\circ }}.\]

We know 1 hour = 60 minutes.

Degree swept by minute hand in 60 minutes = \[{{360}^{\circ }}\]

\[\therefore \]Degree swept by minute hand in 1 minute = \[\dfrac{360}{60}={{6}^{\circ }}\]

\[\therefore \]Degree swept by the minute hand in 1 minute is \[{{6}^{\circ }}\].

Hence, here \[\theta = {{6}^{\circ }}\]and radius r = 14 cm.

Now we need to find the area swept by the minute hand in 1 minute is equal to the shaded portion in the figure, which can be allocated as a sector. Hence we need to find the area of sector in the shaded region.

Area swept by minute hand = Area of sector.

We know, area of the sector,

\[\begin{align}

& = \dfrac{\theta }{360}\times \pi {{r}^{2}} \\

& = \dfrac{6}{360}\times \dfrac{22}{7}\times {{14}^{2}} \\

& = \dfrac{6}{360}\times \dfrac{22}{7}\times 14\times 14 \\

\end{align}\]

Cancel out the like terms and simplify it.

Area of sector

\[\dfrac{1}{60}\times 22\times 2\times 14\times =\dfrac{11\times 14\times 2}{30} = \dfrac{11\times 7\times 2}{15} = \dfrac{77\times 2}{15} = \dfrac{154}{15} = 10.267c{{m}^{2}}\]

\[\therefore \]Area of sector\[ = 10.267c{{m}^{2}}\]

\[\therefore \]Area swept by minute hand\[ = 10.267c{{m}^{2}}\]

Hence option C is the correct answer.

Note:- If we were asked to find the area swept in five minutes, then we first find the degree swept by 1 minute and then find the degree swept by 5 minutes.

Degree swept by 1 minute\[ = {{6}^{\circ }}\]

Degree swept by 5 minutes\[ = {{6}^{\circ }}\times 5={{30}^{\circ }}\]

So, area of sector\[ = \dfrac{30}{360}\times \pi {{r}^{2}} = 51.33c{{m}^{2}} = \]area swept by 5 minutes

Similarly, you can find areas swept by the minute hand for other time periods.

The minute hand of a clock completes a full circle degree in 1 hour. Consider the clock given below. The degree swept by the minute hand in 1 hour is \[{{360}^{\circ }}\] , i.e. the clock resembles circle and the degree of a circle is \[{{360}^{\circ }}\] . Thus it will be easier to remember that the degree swept by minute hand in 1 hour is \[{{360}^{\circ }}.\]

We know 1 hour = 60 minutes.

Degree swept by minute hand in 60 minutes = \[{{360}^{\circ }}\]

\[\therefore \]Degree swept by minute hand in 1 minute = \[\dfrac{360}{60}={{6}^{\circ }}\]

\[\therefore \]Degree swept by the minute hand in 1 minute is \[{{6}^{\circ }}\].

Hence, here \[\theta = {{6}^{\circ }}\]and radius r = 14 cm.

Now we need to find the area swept by the minute hand in 1 minute is equal to the shaded portion in the figure, which can be allocated as a sector. Hence we need to find the area of sector in the shaded region.

Area swept by minute hand = Area of sector.

We know, area of the sector,

\[\begin{align}

& = \dfrac{\theta }{360}\times \pi {{r}^{2}} \\

& = \dfrac{6}{360}\times \dfrac{22}{7}\times {{14}^{2}} \\

& = \dfrac{6}{360}\times \dfrac{22}{7}\times 14\times 14 \\

\end{align}\]

Cancel out the like terms and simplify it.

Area of sector

\[\dfrac{1}{60}\times 22\times 2\times 14\times =\dfrac{11\times 14\times 2}{30} = \dfrac{11\times 7\times 2}{15} = \dfrac{77\times 2}{15} = \dfrac{154}{15} = 10.267c{{m}^{2}}\]

\[\therefore \]Area of sector\[ = 10.267c{{m}^{2}}\]

\[\therefore \]Area swept by minute hand\[ = 10.267c{{m}^{2}}\]

Hence option C is the correct answer.

Note:- If we were asked to find the area swept in five minutes, then we first find the degree swept by 1 minute and then find the degree swept by 5 minutes.

Degree swept by 1 minute\[ = {{6}^{\circ }}\]

Degree swept by 5 minutes\[ = {{6}^{\circ }}\times 5={{30}^{\circ }}\]

So, area of sector\[ = \dfrac{30}{360}\times \pi {{r}^{2}} = 51.33c{{m}^{2}} = \]area swept by 5 minutes

Similarly, you can find areas swept by the minute hand for other time periods.

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